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Let's say I have a const char* that I want to print with std::cout but I only want the first X characters to be printed. Is there a way to tell that to std::cout? (Without inserting a terminating-null into the string or making a temporary copy.)
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You have to write a loop or initialize a std::string with a/2 '*' characters to get that working. Your logic to count number of stars that should get printed is correct.
Then, how to print character? We can use cast type here, by casting into char we are able to get result in character format. We can use cout<<char(65) or cout<<char(var), that will print 'A'. (65 is the ASCII value of 'A').
The printf function (the name comes from “print formatted”) prints a string on the screen using a “format string” that includes the instructions to mix several strings and produce the final string to be printed on the screen.
The task is to print the maximum occurring character in the input string. If 2 or more characters appear the same number of times, print the lexicographically (alphabetically) lowest (first) character. Examples: ‘t’, ‘e’ and ‘s’ appears 2 times, but ‘e’ is the lexicographically smallest character.
Note: More than one variable can be printed using the insertion operator (<<) with cout. Below is the C++ program to implement the above approach: The cout statement can also be used with some member functions:
A character variable can store only a single character. In the example above, we have declared a character type variable named ch. We then assigned the character h to it. Note: In C and C++, a character should be inside single quotation marks. If we use, double quotation marks, it's a string.
Char values are interpreted as ASCII characters. ASCII is an acronym for American Standard Code for Information Interchange. It states a specific way of representing English characters in the form of numbers. To see the ASCII value of a character, we pass it to the int () function.
C++ 17 introduces string_view
#include <string_view>
#include <iostream>
char message[] = { "my long char message" };
int length = some_number;
int main() {
string_view str(message);
std::cout << str.substr(0, length) << std::endl;
}
I have not tried to compile the above code. string_view is basically a string except that it does not 'own' its contents (will not delete the internal pointer after use).
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