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c# ProcessStartInfo.Start - reading output but with a timeout

Tags:

c#

.net

If you want to start another process and wait (with time out) to finish you can use the following (from MSDN).

//Set a time-out value.
int timeOut=5000;
//Get path to system folder.
string sysFolder= 
    Environment.GetFolderPath(Environment.SpecialFolder.System);
//Create a new process info structure.
ProcessStartInfo pInfo = new ProcessStartInfo();
//Set file name to open.
pInfo.FileName = sysFolder + @"\eula.txt";
//Start the process.
Process p = Process.Start(pInfo);
//Wait for window to finish loading.
p.WaitForInputIdle();
//Wait for the process to exit or time out.
p.WaitForExit(timeOut);
//Check to see if the process is still running.
if (p.HasExited == false)
    //Process is still running.
    //Test to see if the process is hung up.
    if (p.Responding)
        //Process was responding; close the main window.
        p.CloseMainWindow();
    else
        //Process was not responding; force the process to close.
        p.Kill();

MessageBox.Show("Code continuing...");

If you want to start another process and read its output then you can use the following pattern (from SO)

// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "Write500Lines.exe";
p.Start();
// Do not wait for the child process to exit before
// reading to the end of its redirected stream.
// p.WaitForExit();
// Read the output stream first and then wait.
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();

How can you combine the two to read all input, not get stuck in deadlock and have a timeout if the running process goes awry?

like image 674
Ryan Avatar asked Apr 19 '11 15:04

Ryan


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1 Answers

You don't have to combine the two - the Process class has an event that fires when output is sent to the StandardOutput - OutputDataReceived.

If you subscribe to the event, you will be able to read output as it arrives and in your main program loop you can still timeout.

like image 144
Oded Avatar answered Sep 27 '22 18:09

Oded