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How to differentiate between overloading the 2 versions of operator ++ ?
const T& operator ++(const T& rhs)
which one?
i++;
++i;
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Increment Operators are the unary operators used to increment or add 1 to the operand value. The Increment operand is denoted by the double plus symbol (++). It has two types, Pre Increment and Post Increment Operators.
In C, ++ and -- operators are called increment and decrement operators. They are unary operators needing only one operand. Hence ++ as well as -- operator can appear before or after the operand with same effect. That means both i++ and ++i will be equivalent.
Definition. Increment Operator is used to increase the value of the operand by 1 whereas the Decrement Operator is used to decrease the value of the operand by 1. In C++, the value of the variable is increased or decreased by 1 with the help of the Increment operator and the Decrement Operator.
The increment(++) and decrement operators(--) are important unary operators in C. Unary operators are those which are applied on a single operand. The increment operator increases the value of the variable by one and the decrement operator decreases the value of the variable by one.
For the non-member versions, a function with one parameter is prefix while a function with two parameters and the second being int is postfix:
struct X {};
X& operator++(X&); // prefix
X operator++(X&, int); // postfix
For the member-versions, the zero-parameter version is prefix and the one-parameter version taking int is postfix:
struct X {
X& operator++(); // prefix
X operator++(int); // postfix
};
The int parameter to calls of the postfix operators will have value zero.
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