I have a class defined as below:
[XmlRoot("ClassName")]
public class ClassName_0
{
//stuff...
}
I then create a list of ClassName_0 like such:
var myListInstance= new List<ClassName_0>();
This is the code I use to serialize:
var ser = new XmlSerializer(typeof(List<ClassName_0>));
ser.Serialize(aWriterStream, myListInstance);
This is the code I use to deserialize:
var ser = new XmlSerializer(typeof(List<ClassName_0>));
var wrapper = ser.Deserialize(new StringReader(xml));
If I serialize it to xml, the resulting xml looks like below:
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfClassName_0 xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<ClassName_0>
<stuff></stuff>
</ClassName_0>
<ClassName_0>
<stuff></stuff>
</ClassName_0>
</ArrayOfClassName_0>
Is there a way to serialize and be able to deserialize the below from/to a list of ClassName_0?
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfClassName xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<ClassName>
<stuff></stuff>
</ClassName>
<ClassName>
<stuff></stuff>
</ClassName>
</ArrayOfClassName>
Thanks!
In your example ClassName isn't the real root. The real root is your list. So you have to mark the list as the root element. Your class is just an XmlElement.
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