Byte to Binary String C# - Display all 8 digits

Question

I want to display one byte in textbox. Now I'm using:

Convert.ToString(MyVeryOwnByte, 2); 

But when byte is has 0's at begining those 0's are being cut. Example:

MyVeryOwnByte = 00001110 // Texbox shows -> 1110 MyVeryOwnByte = 01010101 // Texbox shows -> 1010101 MyVeryOwnByte = 00000000 // Texbox shows -> <Empty> MyVeryOwnByte = 00000001 // Texbox shows -> 1 

I want to display all 8 digits.

Answer 1

Convert.ToString(MyVeryOwnByte, 2).PadLeft(8, '0'); 

This will fill the empty space to the left with '0' for a total of 8 characters in the string

Answer 2

How you do it depends on how you want your output to look.

If you just want "00011011", use a function like this:

static string Pad(byte b) {     return Convert.ToString(b, 2).PadLeft(8, '0'); } 

If you want output like "00011011", use a function like this:

static string PadBold(byte b) {     string bin = Convert.ToString(b, 2);     return new string('0', 8 - bin.Length) + "<b>" + bin + "</b>"; } 

If you want output like "0001 1011", a function like this might be better:

static string PadNibble(byte b) {     return Int32.Parse(Convert.ToString(b, 2)).ToString("0000 0000"); }