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$ bc
BC> ibase=2
BC> 110&101 // wanna get 100
(standar_in) 8: syntax error
Wikipedia informs that the ops are "|, & and ^". It may be that they work only in certain BC-types or I misread something.
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In the C programming language, operations can be performed on a bit level using bitwise operators. Bitwise operations are contrasted by byte-level operations which characterize the bitwise operators' logical counterparts, the AND, OR, NOT operators.
There are six different types of Bitwise Operators in C.
The ^ (bitwise XOR) in C or C++ takes two numbers as operands and does XOR on every bit of two numbers. The result of XOR is 1 if the two bits are different. The << (left shift) in C or C++ takes two numbers, left shifts the bits of the first operand, the second operand decides the number of places to shift.
Despite bc won't do it, you can use arithmetic expansion directly on the terminal if you use bash.
To XOR 44 and 61, you can do:
echo $((44^61))
If you want to use binary code, then:
echo $((2#110^2#101))
See Numerical Constants for changing the base.
See bitwise operators section to peep at available operators.
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