I'm a bit confused because I wanted to initialize a variable of type unsigned long
whose size is 8 bytes on my system (on every modern system I suppose). When I want to assign 1 << 63
to the variable, I get a compiler warning however and the number is in fact 0. When I do 1 << 30
I get the expected result of 2 ^ 30 = 1073741824
. Yet when I do 1 << 31
, I get the result of 2 ^ 64
(I think; actually this shouldn't be possible) which prints 18446744071562067968
.
Can anyone explain this behaviour to me?
1 << 63
will be computed in int
arithmetic, and your int
is probably 32 bit.
Remedy this by promoting one of the arguments: 1ULL << 63
will do it.
ULL
means the expression will be at least 64 bits.
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