Menu
How can a global script variable be passed to the command of xargs? I tried it this way:
TEST=hallo2
echo "hallo" | xargs sh -c 'echo passed=$1 test=$TEST' sh
Output:
passed=hallo test=
I know I could use the {} token but I need to do it this way!
I'm using bash.
660
xargs options : -0 : input items are terminated by null character instead of white spaces. -a file : read items from file instead of standard input.
xargs gets the needed arguments from standard input (the standard input). Different options tell how the standard input is to be interpreted to obtain these arguments. -I placeholder Specifies that each line in the standard input (the standard input) is to be considered as a single argument.
xargs command in UNIX or Linux is a powerful command used in conjunction with find and grep command in UNIX to divide a big list of arguments into small list received from standard input.
Added as an answer as@chepner suggested.
export the variable TEST:
export TEST=hallo2
echo "hallo" | xargs sh -c 'echo passed=$1 test="$TEST"' sh
Take variable $TEST out from the quotes:
TEST=hallo2
echo "hallo" | xargs sh -c 'echo passed=$1 test='$TEST sh
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
