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Bash script: always show menu after loop execution

I'm using a bash script menu like this:

#!/bin/bash
PS3='Please enter your choice: '
options=("Option 1" "Option 2" "Option3" "Quit")
select opt in "${options[@]}"
do
    case $opt in
        "Option 1")
            echo "you chose choice 1"
            ;;
        "Option 2")
            echo "you chose choice 2"
            ;;
        "Option 3")
            echo "you chose choice 3"
            ;;
        "Quit")
            break
            ;;
        *) echo invalid option;;
    esac
done

After each menu selection I just get prompted with

Please enter your choice:

How do I always show the menu after each option has finished execution? I've done some looking around and I think I can do some kind of while loop, but I haven't been able to get anything working.

like image 749
EightBall Avatar asked Nov 26 '13 18:11

EightBall


2 Answers

Make it beautiful and userfriendly ;-)

#!/bin/bash

while :
do
    clear
    cat<<EOF
    ==============================
    Menusystem experiment
    ------------------------------
    Please enter your choice:

    Option (1)
    Option (2)
    Option (3)
           (Q)uit
    ------------------------------
EOF
    read -n1 -s
    case "$REPLY" in
    "1")  echo "you chose choice 1" ;;
    "2")  echo "you chose choice 2" ;;
    "3")  echo "you chose choice 3" ;;
    "Q")  exit                      ;;
    "q")  echo "case sensitive!!"   ;; 
     * )  echo "invalid option"     ;;
    esac
    sleep 1
done

Replace the echos in this example with function calls or calls to other scripts.

like image 195
thom Avatar answered Oct 04 '22 23:10

thom


just modified your script like below. its working for me !

 #!/bin/bash
 while true
 do
 PS3='Please enter your choice: '
 options=("Option 1" "Option 2" "Option 3" "Quit")
 select opt in "${options[@]}" 
 do
     case $opt in
         "Option 1")
             echo "you chose choice 1"
             break
             ;;
         "Option 2")
             echo "you chose choice 2"
             break
             ;;
         "Option 3")
             echo "you chose choice 3"
             break
             ;;
         "Quit")
             echo "Thank You..."                 
             exit
             ;;
         *) echo invalid option;;
     esac
 done
 done
like image 42
Ranjithkumar T Avatar answered Oct 05 '22 01:10

Ranjithkumar T