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I use startx to start X which will evaluate my .xinitrc. In my .xinitrc I start my window manager using /usr/bin/mywm. Now, if I kill my WM (in order to f.e. test some other WM), X will terminate too because the .xinitrc script reached EOF. So I added this at the end of my .xinitrc:
while true; do sleep 10000; done This way X won't terminate if I kill my WM. Now my question: how can I do an infinite sleep instead of looping sleep? Is there a command which will kinda like freeze the script?
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The bash shell does not have a builtin usleep command (nor does it have a builtin sleep command).
Infinite while Loop You can also use the true built-in or any other statement that always returns true. The while loop above will run indefinitely. You can terminate the loop by pressing CTRL+C .
Which results in: TIME_T_MAX = 9223372036854775807 . That is: sleep infinite results in an actual sleep time of 9223372036854775807 seconds (10^11 years). And for 32-bit linux systems ( sizeof(long) is 4 (32 bits)): 2147483647 seconds (68 years; see also year 2038 problem).
/bin/sleep is Linux or Unix command to delay for a specified amount of time. You can suspend the calling shell script for a specified time. For example, pause for 10 seconds or stop execution for 2 mintues. In other words, the sleep command pauses the execution on the next shell command for a given time.
sleep infinity does exactly what it suggests and works without cat abuse.
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