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Assembly memory allocation

I am trying to learn assembly language and I need clarification on something. Please correct me if I am wrong on any of this since I don't know much about assembly.

All the tutorials I watch have the variables of assembly programs assigned to a memory address like 0x0000, and I can understand that you must manually assign memory addresses in assembly, but how do you know what address to use?

Obviously it makes sense to start at the lowest memory address possible, but what if the variable you are assigning is larger than the memory available at 0x0000? Would the variable in question run over to 0x0001 or 0x0002? If it did wouldn't that mess up other variables assigned spaces with similar numbering (or are you not supposed to assign them that close)?

If I have two programs written in assembly running at the same time (in a modern OS) and I have used the same memory addresses in both programs, will one program conflict with the other, or does the OS just assign an available memory address regardless of what was actually written in the program?

Any information on the subject is appreciated.

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ubiquibacon Avatar asked Aug 17 '10 00:08

ubiquibacon


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2 Answers

The answer to the second part of you question (on most modern OSs) is virtual memory.

You start at the hardware layer with physical memory. That's the stuff you can actually poke with your finger. This is what the operating system sees. The operating system lets you run processes on an abstraction called virtual memory.

Each process gets its own virtual memory space. So it can pretend that it's the only process running, and it has tons of memory. Then each time you access memory, you supply a virtual address, which gets mapped to a physical address. The operating system keeps a table of which virtual address gets mapped to which actual physical addresses in RAM. Typically this is done with some special hardware as well (an MMU, memory management unit) for performance reasons, but you could do it 100% in software too.

So when you say 0x000 in your program, that's a virtual address. It gets translated into a physical address by the computer when you read or write. So in another process, the same virtual address 0x000 maps to a different physical address. This system lets you write your program without knowing exactly how much RAM is available, or what address your program will be loaded into. It also prevents your program from trashing memory that belongs to another program.

As for the first part, absolutely. Different types of data take different amounts of memory. You have to know how much space you need when you lay out your data structures. There are also byte-alignment issues to keep in mind. Multi-byte data types (eg floating point numbers) often have to start at an address that is divisible by 2 or 4 or the number of bytes it takes to store a float -- it's a requirement of the processor or the RAM. So you can't just crunch all your data together, one byte after the next, you have to lay it out in a specific order like fitting together the pieces of a puzzle if you want to minimize unused memory.

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Alex Martini Avatar answered Oct 20 '22 01:10

Alex Martini


This is not exactly an answer but in this book there is the answer. I can only recommend it. It will teach you the basics, like the name says it's Programming from ground up.

ProgrammingGroundUp

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Octavian A. Damiean Avatar answered Oct 20 '22 03:10

Octavian A. Damiean