Arithmetic problem with shell script

Question

I've got some issues on scripting... if someone could help me, it would be really good !

My script has:

VISITS=$((WR + RD));
SERVICE_DEMAND=$((VISITS*SERVICE_DEMAND));

And I'm getting this error:

./calc_serv_demand.sh: line 12: 0.0895406: syntax error: invalid arithmetic operator (error token is ".0895406")

Can someone help me?

I think it's because the bash works only with integer... I need to use float values, though.

thanks in advance

---

Problem solved:

VISITS=$(echo $WR + $RD | bc); echo $VISITS

SERVICE_DEMAND=$(echo $VISITS '*' $SERVICE_TIME | bc); echo $SERVICE_DEMAND

Answer 1

You can use bc to do your floating point calculations, i.e.

echo $WR + $RD | bc

and so on.