Are temporary objects in C++ const indeed?

Question

I always believed that temporary objects in C++ are automatically considered as const by the compiler. But recently I experienced that the following example of code:

function_returning_object().some_non_const_method();

is valid for C++ compiler. And it makes me wonder - are temporary objects in C++ const indeed? If yes, then why the code above is considered correct by the compiler?

Answer 1

No, they're not. Not unless you declare the return type as const.