Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

C++'s default inheritance access specifier? [duplicate]

Tags:

c++

gcc

I have some legacy code that I have to wrap, and I have come across this declaration:

class Foo : Bar
{
    // ...
};

This seems to compile under GCC. I know it's bad, but I can't change it. My question is, if no inheritance access specifier is present, how does the C++ compiler handle it?

like image 370
Ross Light Avatar asked Nov 30 '22 09:11

Ross Light


2 Answers

For classes, the default is private.

For structs, the default is public.

like image 50
Justin Ardini Avatar answered Dec 22 '22 07:12

Justin Ardini


BTW, it is not called access modifier. It is called access specifier

$11.2/2 - "In the absence of an access-specifier for a base class, public is assumed when the derived class is defined with the class-key struct and private is assumed when the class is defined with the class-key class."

In your context, 'Bar' is a private base class of 'Foo'

like image 42
Chubsdad Avatar answered Dec 22 '22 06:12

Chubsdad