Doing the Y-Combinator for a single argument function such as factorial or fibonacci in Clojure is well documented: http://rosettacode.org/wiki/Y_combinator#Clojure
My question is - how do you do it for a two argument function such as this getter for example?
(Assumption here is that I want to solve this problem recursively and this non-idiomatic clojure code is there deliberately for another reason)
[non y-combinator version]
(defn get_ [n lat]
(cond
(empty? lat) ()
(= 0 (- n 1)) (first lat)
true (get_ (- n 1) (rest lat))))
(get_ 3 '(a b c d e f g h i j))
The number of args doesn't change anything since the args
are apply
'd. You just need to change the structure of get_
:
(defn get_ [f] (fn [n lat] (cond (empty? lat) () (= 1 n) (first lat) :else (f (dec n) (next lat))))) (defn Y [f] ((fn [x] (x x)) (fn [x] (f (fn [& args] (apply (x x) args))))))
user=> ((Y getf) 3 '(a b c d e f g h i j)) c
It'd be pretty straight forward.
Say you've got a function H:
(def H
(fn [x]
(fn [x y]
(stuff happens))))
Then you apply the same ol' Y-Combinator:
((Y H) 4 5)
Where 4
and 5
are arguments you want to pass to H.
The combinator is essentially "dealing with" the top-level function in H, not the one that's doing the hard work (the one with arity 2, here).
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