Any way to exit outer function from within inner function?

Question

Within PHP, if I have one function that calls another function; is there any way to get the called function to exit out of the caller function without killing the entire script?

For instance, let's say I have some code something like:

<?php
function funcA() {
    funcB();
    echo 'Hello, we finished funcB';
}

function funcB() {
    echo 'This is funcB';
}
?>
<p>This is some text. After this text, I'm going to call funcA.</p>
<p><?php funcA(); ?></p>
<p>This is more text after funcA ran.</p>

Unfortunately, if I find something inside of funcB that makes me want to stop funcA from finishing, I seem to have to exit the entire PHP script. Is there any way around this?

I understand that I could write something into funcA() to check for a result from funcB(), but, in my case, I have no control over the contents of funcA(); I only have control over the contents of funcB().

To make this example a little more concrete; in this particular instance, I am working with WordPress. I am hooking into the get_template_part() function, and trying to stop WordPress from actually requiring/including the file through the locate_template() function that's called after my hook is executed.

Does anyone have any advice?

Answer 1

Throw an exception in funcB that is not handled in funcA