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Android - get children inside a View?

Tags:

android

view

People also ask

What is child view in android?

In android (and most other technologies), views can have subviews, aka "children". Most views can have children and can be a child of a parent view. It's kind of like a "tree". The most obvious feature of being a child of some other view is that the child moves with the parent view.

What is a ViewGroup in android?

ViewGroup is a collection of Views(TextView, EditText, ListView, etc..), somewhat like a container. A View object is a component of the user interface (UI) like a button or a text box, and it's also called a widget.

What is view and view group?

View is a basic building block of UI (User Interface) in android. A view is a small rectangular box which responds to user inputs. Eg: EditText , Button , CheckBox , etc.. ViewGroup is a invisible container of other views (child views) and other viewgroups.

Whats a view group?

ViewGroup. A ViewGroup is a special view that can contain other views. The ViewGroup is the base class for Layouts in android, like LinearLayout , RelativeLayout , FrameLayout etc. In other words, ViewGroup is generally used to define the layout in which views(widgets) will be set/arranged/listed on the android screen.


for(int index = 0; index < ((ViewGroup) viewGroup).getChildCount(); index++) {
    View nextChild = ((ViewGroup) viewGroup).getChildAt(index);
}

Will that do?


If you not only want to get all direct children but all children's children and so on, you have to do it recursively:

private ArrayList<View> getAllChildren(View v) {

    if (!(v instanceof ViewGroup)) {
        ArrayList<View> viewArrayList = new ArrayList<View>();
        viewArrayList.add(v);
        return viewArrayList;
    }

    ArrayList<View> result = new ArrayList<View>();

    ViewGroup vg = (ViewGroup) v;
    for (int i = 0; i < vg.getChildCount(); i++) {

        View child = vg.getChildAt(i);

        ArrayList<View> viewArrayList = new ArrayList<View>();
        viewArrayList.add(v);
        viewArrayList.addAll(getAllChildren(child));

        result.addAll(viewArrayList);
    }
    return result;
}

To use the result you could do something like this:

    // check if a child is set to a specific String
    View myTopView;
    String toSearchFor = "Search me";
    boolean found = false;
    ArrayList<View> allViewsWithinMyTopView = getAllChildren(myTopView);
    for (View child : allViewsWithinMyTopView) {
        if (child instanceof TextView) {
            TextView childTextView = (TextView) child;
            if (TextUtils.equals(childTextView.getText().toString(), toSearchFor)) {
                found = true;
            }
        }
    }
    if (!found) {
        fail("Text '" + toSearchFor + "' not found within TopView");
    }

You can always access child views via View.findViewById() http://developer.android.com/reference/android/view/View.html#findViewById(int).

For example, within an activity / view:

...
private void init() {
  View child1 = findViewById(R.id.child1);
}
...

or if you have a reference to a view:

...
private void init(View root) {
  View child2 = root.findViewById(R.id.child2);
}

I'm just going to provide this answer as an alternative @IHeartAndroid's recursive algorithm for discovering all child Views in a view hierarchy. Note that at the time of this writing, the recursive solution is flawed in that it will contains duplicates in its result.

For those who have trouble wrapping their head around recursion, here's a non-recursive alternative. You get bonus points for realizing this is also a breadth-first search alternative to the depth-first approach of the recursive solution.

private List<View> getAllChildrenBFS(View v) {
    List<View> visited = new ArrayList<View>();
    List<View> unvisited = new ArrayList<View>();
    unvisited.add(v);

    while (!unvisited.isEmpty()) {
        View child = unvisited.remove(0);
        visited.add(child);
        if (!(child instanceof ViewGroup)) continue;
        ViewGroup group = (ViewGroup) child;
        final int childCount = group.getChildCount();
        for (int i=0; i<childCount; i++) unvisited.add(group.getChildAt(i));
    }

    return visited;
}

A couple of quick tests (nothing formal) suggest this alternative is also faster, although that has most likely to do with the number of new ArrayList instances the other answer creates. Also, results may vary based on how vertical/horizontal the view hierarchy is.

Cross-posted from: Android | Get all children elements of a ViewGroup


Here is a suggestion: you can get the ID (specified e.g. by android:id="@+id/..My Str..) which was generated by R by using its given name (e.g. My Str). A code snippet using getIdentifier() method would then be:

public int getIdAssignedByR(Context pContext, String pIdString)
{
    // Get the Context's Resources and Package Name
    Resources resources = pContext.getResources();
    String packageName  = pContext.getPackageName();

    // Determine the result and return it
    int result = resources.getIdentifier(pIdString, "id", packageName);
    return result;
}

From within an Activity, an example usage coupled with findViewById would be:

// Get the View (e.g. a TextView) which has the Layout ID of "UserInput"
int rID = getIdAssignedByR(this, "UserInput")
TextView userTextView = (TextView) findViewById(rID);

As an update for those who come across this question after 2018, if you are using Kotlin, you can simply use the Android KTX extension property ViewGroup.children to get a sequence of the View's immediate children.


This method takes all views inside a layout, this is similar to Alexander Kulyakhtin's answer. The difference is, it accepts any type of parent layouts & returns an Array List of views.

public List<View> getAllViews(ViewGroup layout){
        List<View> views = new ArrayList<>();
        for(int i =0; i< layout.getChildCount(); i++){
            views.add(layout.getChildAt(i));
        }
        return views;
}