Alphabet range in Python

Question

Instead of making a list of alphabet characters like this:

alpha = ['a', 'b', 'c', 'd'.........'z'] 

is there any way that we can group it to a range or something? For example, for numbers it can be grouped using range():

range(1, 10) 

Answer 1

>>> import string >>> string.ascii_lowercase 'abcdefghijklmnopqrstuvwxyz' 

If you really need a list:

>>> list(string.ascii_lowercase) ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] 

And to do it with range

>>> list(map(chr, range(97, 123))) #or list(map(chr, range(ord('a'), ord('z')+1))) ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] 

Other helpful string module features:

>>> help(string) # on Python 3 .... DATA     ascii_letters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'     ascii_lowercase = 'abcdefghijklmnopqrstuvwxyz'     ascii_uppercase = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'     digits = '0123456789'     hexdigits = '0123456789abcdefABCDEF'     octdigits = '01234567'     printable = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~ \t\n\r\x0b\x0c'     punctuation = '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'     whitespace = ' \t\n\r\x0b\x0c'