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Suppose the following:
>>> s = set([1, 2, 3]) How do I get a value (any value) out of s without doing s.pop()? I want to leave the item in the set until I am sure I can remove it - something I can only be sure of after an asynchronous call to another host.
Quick and dirty:
>>> elem = s.pop() >>> s.add(elem) But do you know of a better way? Ideally in constant time.
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The remove() method removes the specified element from the set. This method is different from the discard() method, because the remove() method will raise an error if the specified item does not exist, and the discard() method will not.
We can access the first item in the set by using iter() function, we have to apply next() to it to get the first element.
Python slice() FunctionThe slice() function returns a slice object. A slice object is used to specify how to slice a sequence. You can specify where to start the slicing, and where to end. You can also specify the step, which allows you to e.g. slice only every other item.
Two options that don't require copying the whole set:
for e in s: break # e is now an element from s Or...
e = next(iter(s)) But in general, sets don't support indexing or slicing.
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