Adding header for HttpURLConnection

Question

I have used the following code in the past and it had worked with basic authentication enabled in TomCat:

URL myURL = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)myURL.openConnection();

String userCredentials = "username:password";
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userCredentials.getBytes()));

myURLConnection.setRequestProperty ("Authorization", basicAuth);
myURLConnection.setRequestMethod("POST");
myURLConnection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
myURLConnection.setRequestProperty("Content-Length", "" + postData.getBytes().length);
myURLConnection.setRequestProperty("Content-Language", "en-US");
myURLConnection.setUseCaches(false);
myURLConnection.setDoInput(true);
myURLConnection.setDoOutput(true);

You can try the above code. The code above is for POST, and you can modify it for GET

Just cause I don't see this bit of information in the answers above, the reason the code snippet originally posted doesn't work correctly is because the encodedBytes variable is a byte[] and not a String value. If you pass the byte[] to a new String() as below, the code snippet works perfectly.

encodedBytes = Base64.encode(authorization.getBytes(), 0);
authorization = "Basic " + new String(encodedBytes);

If you are using Java 8, use the code below.

URLConnection connection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) connection;

String basicAuth = Base64.getEncoder().encodeToString((username+":"+password).getBytes(StandardCharsets.UTF_8));
httpConn.setRequestProperty ("Authorization", "Basic "+basicAuth);

Finally this worked for me

private String buildBasicAuthorizationString(String username, String password) {

    String credentials = username + ":" + password;
    return "Basic " + new String(Base64.encode(credentials.getBytes(), Base64.NO_WRAP));
}

Your code is fine.You can also use the same thing in this way.

public static String getResponseFromJsonURL(String url) {
    String jsonResponse = null;
    if (CommonUtility.isNotEmpty(url)) {
        try {
            /************** For getting response from HTTP URL start ***************/
            URL object = new URL(url);

            HttpURLConnection connection = (HttpURLConnection) object
                    .openConnection();
            // int timeOut = connection.getReadTimeout();
            connection.setReadTimeout(60 * 1000);
            connection.setConnectTimeout(60 * 1000);
            String authorization="xyz:xyz$123";
            String encodedAuth="Basic "+Base64.encode(authorization.getBytes());
            connection.setRequestProperty("Authorization", encodedAuth);
            int responseCode = connection.getResponseCode();
            //String responseMsg = connection.getResponseMessage();

            if (responseCode == 200) {
                InputStream inputStr = connection.getInputStream();
                String encoding = connection.getContentEncoding() == null ? "UTF-8"
                        : connection.getContentEncoding();
                jsonResponse = IOUtils.toString(inputStr, encoding);
                /************** For getting response from HTTP URL end ***************/

            }
        } catch (Exception e) {
            e.printStackTrace();

        }
    }
    return jsonResponse;
}

Its Return response code 200 if authorizationis success

With RestAssurd you can also do the following:

String path = baseApiUrl; //This is the base url of the API tested
    URL url = new URL(path);
    given(). //Rest Assured syntax 
            contentType("application/json"). //API content type
            given().header("headerName", "headerValue"). //Some API contains headers to run with the API 
            when().
            get(url).
            then().
            statusCode(200); //Assert that the response is 200 - OK