I have a data frame like this, with different observations for each id:
library(dplyr)
df <- data.frame(id=c(1,1,1,1,1,2,2,3), v1= rnorm(8), v2=rnorm(8))
I then group by id:
by_id <- group_by(df, id)
Now I want to calculate mean and sd of the observations of v1 for each id. This is easy with summarise:
df2 <- summarise(by_id,
                    v1.mean=mean(v1),
                    v1.sd=sd(v1))
Now I want to add the slope of a linear regression of v1 and v2
df2 <- summarise(by_id,
                   v1.mean=mean(v1),
                   v1.sd=sd(v1),
                   slope=as.vector(coef(lm(v1~v2,na.action="na.omit")[2])))
However, this fails, I think because one person (id=3) has only one observation and thus cannot build a linear model.
I also tried
   slope=ifelse(n()==1,0,as.vector(coef(lm(v1~v2,na.action="na.omit")[2]))))
but it does not work either. Is there an easy solution for this?
Not that it may also be the case that if I have more than one observation but for example v2 has a missing value, so the lm might also fail.
you can try this
group_by(df, id) %>% do(fit = lm(v1~v2, .)) %>% summarise(intercept = coef(fit)[1],  slope= coef(fit)[2])
Source: local data frame [3 x 2]
   intercept     slope
1 -0.3116880 0.2698022
2 -1.2303663 0.4949600
3  0.3169372        NA
note the use of do and . inside the lm function.
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