Add all elements of an iterable to list

Question

Is there a more concise way of doing the following?

t = (1,2,3) t2 = (4,5)  l.addAll(t) l.addAll(t2) print l # [1,2,3,4,5] 

This is what I have tried so far: I would prefer to avoid passing in the list in the parameters.

def t_add(t,stuff):     for x in t:         stuff.append(x) 

Answer 1

Use list.extend(), not list.append() to add all items from an iterable to a list:

l.extend(t) l.extend(t2) 

or

l.extend(t + t2) 

or even:

l += t + t2 

where list.__iadd__ (in-place add) is implemented as list.extend() under the hood.

Demo:

>>> l = [] >>> t = (1,2,3) >>> t2 = (4,5) >>> l += t + t2 >>> l [1, 2, 3, 4, 5] 

If, however, you just wanted to create a list of t + t2, then list(t + t2) would be the shortest path to get there.