Menu
I want to get the last element of $*. The best I've found so far is:
last=`eval "echo \\\$$#"`
But that seems overly opaque.
858
We can also access all command line arguments by shifting their position in a shell script. Like access your first command line argument with $1. Now shift arguments with 1. It means the second argument is now at first position, similarity third is at second and so on.
Instead of prompting the user for the filename, we can make the user simply pass the filename as a command line argument while running the script as follows: The first bash argument (also known as a positional parameter) can be accessed within your bash script using the $1 variable.
You can pass more than one argument to your bash script. In general, here is the syntax of passing multiple arguments to any bash script: script.sh arg1 arg2 arg3 …. The second argument will be referenced by the $2 variable, the third argument is referenced by $3, .. etc. The $0 variable contains the name of your bash script in case you were ...
Bash Shell arguments, bash, script, shell. A Command-line Arguments are passed after the name of a program in command-line operating systems like DOS or Linux and are passed into the program from the operating system. Shell scripts also accept command line arguments similar to nix commands.
In zsh, you can either use the P parameter expansion flag or treat @ as an array containing the positional parameters:
last=${(P)#}
last=${@[$#]}
A way that works in all Bourne-style shells including zsh is
eval last=\$$#
(You were on the right track, but running echo just to get its output is pointless.)
86
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
