zipped array returns as <zip object at 0x02B6F198>

Question

I have two arrays: X = [1,2,3,4,5,3,8] and Y = ['S', 'S', 'S', 'S', 'S', 'C', 'C']. when i print the zipped array of this, it produces <zip object at 0x02B6F198>. The reason these two arrays are zipped is so I can sort Y corresponding to sorted(X) in the line

sortedY = [y for x,y in sorted(zip(X,Y))]

This line of code doesn't sort Y how I would want (sortedY = ['S','S','C','S','S','S','C']) but SortedX stays in the same arrangement as X.

I have a second program in which I use this code and it works fine but this program is significantly smaller in size than the original program.

Answer 1

If you are trying to print the zipped lists directly then that won't work. zipreturns an object and so when you try to print it you just get the object method. If you want to see it as a list, then apply an operation that returns a list.

X = [1,2,3,4,5,3,8]
Y = ['S', 'S', 'S', 'S', 'S', 'C', 'C']

# Some Simple Methods Include
print(list(zip(X, Y)))
print([i for i in zip(X, Y)])

# Output
[(1, 'S'), (2, 'S'), (3, 'S'), (4, 'S'), (5, 'S'), (3, 'C'), (8, 'C')]

Now I'm not sure what the issue was though, as what you provided should be working

sortedY = [y for x,y in sorted(zip(X,Y))]
print(sortedY)

# Output
['S', 'S', 'C', 'S', 'S', 'S', 'C']

As you can see it sorts Y corresponding to sorted X

print(sorted(zip(X,Y)))

#Output (X, Y)
[(1, 'S'), (2, 'S'), (3, 'C'), (3, 'S'), (4, 'S'), (5, 'S'), (8, 'C')]