I have written the following code:
private static <T> T getMax(T[] array) {
if(array.length == 0) {
return null;
}
T max = array[0];
for (int i = 1; i < array.length; i++) {
if (array[i] > max)
max = array[i];
}
return max;
}
The problem is in this line: if(array[i] > max)
.
I understand that Java can't understand the >
operator in case of unknown/arbitrary classes.
At the same time, I don't want to write different methods for the objects of the classes that I know I'll be sending.
Is there a workaround?
Example: Create a Generics Method Here, the type parameter <T> is inserted after the modifier public and before the return type void . We can call the generics method by placing the actual type <String> and <Integer> inside the bracket before the method name. demo. <String>genericMethod("Java Programming"); demo.
Java Generic methods and generic classes enable programmers to specify, with a single method declaration, a set of related methods, or with a single class declaration, a set of related types, respectively. Generics also provide compile-time type safety that allows programmers to catch invalid types at compile time.
For example, classes like HashSet, ArrayList, HashMap, etc., use generics very well. There are some fundamental differences between the two approaches to generic types.
You need to change T
to T extends Comparable<T>
and use the compareTo
method. That is:
private static <T extends Comparable<T>> T getMax(T[] array)
, andif (array[i].compareTo(max) > 0) { ... }
But note that you can use
maxElement = Collections.max(Arrays.asList(array));
Yes, there is a workaround, by adding a Comparable
upper bound to T
.
Because the <
operator doesn't work on objects, you must use the equivalent functionality, which is the compareTo
method in the Comparable
interface.
Ensure that the type T
is Comparable
by providing an upper bound.
private static <T extends Comparable<T>> T getMax(T[] array)
Then, in place of the >
operator, call compareTo
:
if(array[i].compareTo(max) > 0)
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