XSLT set default value when selected one is not available

Question

Is it possible to set a default value using <xsl:value-of>? I am attempting to produce JSON output with an XSLT stylesheet and certain fields might not be available during the processing stage. This leaves a null value which breaks the validity of the JSON document. Ideally I'd be able to set a default value if one is not available. So in the case of:

    "foo_count": <xsl:value-of select="count(foo)" />

If <foo> is not available in the document, can I just set this to 0 somehow?

Answer 1

XSLT/XPath 2

Using Sequence Expressions:

<xsl:value-of select="(foo,0)[1]"/>

Explanation

One way to construct a sequence is by using the comma operator, which evaluates each of its operands and concatenates the resulting sequences, in order, into a single result sequence.

Answer 2

XSLT/XPath 2.0

You can use a Conditional Expressions (if…then…else) on your @select expression:

<xsl:value-of select="if (foo) then foo else 0" />

Answer 3

It is either choose

<xsl:choose>
   <xsl:when test="foo">
     <xsl:value-of select="count(foo)" />
   </xsl:when>
   <xsl:otherwise>
     <xsl:text>0</xsl:text>
   </xsl:otherwise>
 </xsl:choose> 

or use if test

<xsl:if test="foo">
  <xsl:value-of select="count(foo)" />
</xsl:if>
<xsl:if test="not(foo)">
  <xsl:text>0</xsl:text>
</xsl:if>

or use a named template for calling

<xsl:template name="default">
  <xsl:param name="node"/>
  <xsl:if test="$node">
      <xsl:value-of select="count($node)" />
    </xsl:if>
    <xsl:if test="not($node)">
      <xsl:text>0</xsl:text>
  </xsl:if>
</xsl:template>

 <!-- use this in your actual translate -->
 <xsl:call-template name="default">
         <xsl:with-param name="node" select="."/>
 </xsl:call-template>