xslt call java instance method

Question

my xsl looks like below :

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" 
xmlns:SimpleDateFormat="java.text.SimpleDateFormat"
xmlns:Date="java.util.Date" exclude-result-prefixes="SimpleDateFormat Date">

<xsl:variable name="s" select="SimpleDateFormat:new(MMM/dd/yyyy-HH/mm/ss/SSS)"/>
<xsl:variable name="date" select="Date:new(number($beginTime))"/>

So now how to call the method format(Date date) of instance 's'?

If I use <xsl:value-of select="s:format($date)" />, then the error is : prefix must resolve to a namespace : s.

But if I add the namespace like this : xmlns:s="java.text.SimpleDateFormat", the <xsl:value-of select="s:format($date)" /> will return default format, not the specified format.

So how can I get the specified format, like MM/dd/yyyy-HH/mm/ss/SSS ?

Answer 1

The namespace you need to use is the one which refers to the object type, and pass the variable itself as the first argument in your call:

BTW: You need to put the format argument between apostrophes:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:SimpleDateFormat="java.text.SimpleDateFormat" xmlns:Date="java.util.Date" exclude-result-prefixes="SimpleDateFormat Date">
    <xsl:variable name="s" select="SimpleDateFormat:new('MMM/dd/yyyy-HH/mm/ss/SSS')"/>
    <xsl:variable name="date" select="Date:new()"/>
    <!-- +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ -->
    <xsl:template match="*">
        <Test>
            <xsl:value-of select="SimpleDateFormat:format($s,$date)" />
        </Test>
    </xsl:template>
</xsl:stylesheet>

I hope this helps!