I'm trying the find a xml node with xpath query. but i cannot make it working. In firefox result is always "undefined" and chrome throws a error code.
<script type="text/javascript">
var xmlString = '<form><name>test</name></form>';
var doc = new DOMParser().parseFromString(xmlString,'text/xml');
var result = doc.evaluate('/form/name', doc,
null, XPathResult.ANY_TYPE, null);
alert(result.stringValue);
</script>
what's wrong with this code ?
I don't know why did you get this error, but you can change XPathResult.ANY_TYPE
to XPathResult.STRING_TYPE
and will works (tested in firefox 3.6).
See:
var xmlString = '<form><name>test</name></form>';
var doc = new DOMParser().parseFromString(xmlString,'text/xml');
var result = doc.evaluate('/form/name', doc, null, XPathResult.STRING_TYPE, null);
alert(result.stringValue); // returns 'test'
See in jsfiddle.
DETAILS:
The 4th parameter of method evaluate
is a integer where you specify what kind of result do you need (reference). There are many types, as integer, string and any type. This method returns a XPathResult, that has many properties.
You must match the property (numberValue, stringValue) with the property used in evaluate.
I just don't understand why any type
didn't work with string value
.
XPathResult.ANY_TYPE
would return a node set for xpath expression /form/name
, so result.stringValue
would have trouble converting node set to string. In this case you could use result.iterateNext().textContent
However, an expression like count(/form/name)
would return a number value when used with XPathResult.ANY_TYPE
and you could use result.numberValue
to retrieve the number in that case.
Some more detailed explanation at https://developer.mozilla.org/en/DOM/document.evaluate#Result_types
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