XPath test to identify node type

Question

I don't understand why this test

count(.|../@*)=count(../@*) 

( from Dave Pawson's Home page )

identify an attribute node :(

could someone give me a detailled explanation ?

Answer 1

A few things to understand:

1. . refers to the current node (aka "context node")
2. an attribute node has a parent (the element it belongs to)
3. an XPath union operation (with |) never duplicates nodes, i.e. (.|.) results in one node, not two
4. there is the self:: axis you could use in theory (e.g. self::* works to find out if a node is an element), but self::@* does not work, so we must use something different

Knowing that, you can say:

• ../@* fetches all attributes of the current node's parent (all "sibling attributes", if you will)
• (.|../@*) unions the current node with them – if the current node is an attribute, the overall count does not change (as per #3 above)
• therefore, if count(.|../@*) equals count(../@*), the current node must be an attribute node.