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I have the following XML structure.
<?xml version="1.0" encoding="UTF-8"?>
<root>
<header>
<row>
<column n="name" />
<column n="age" />
<column n="email" />
</row>
</header>
<body>
<row>
<column>Foo</column>
<column>99</column>
<column>foo@test.com</column>
</row>
</body>
</root>I'm using the following XPath expression to get the header columns and likewise to get the body columns.
PathExpression headerExpr = xPath.compile("/root/header/row/column/@n");
NodeList headerColumns = (NodeList) headerExpr.evaluate(document, XPathConstants.NODESET);
PathExpression bodyExpr = xPath.compile("/root/body/row/column");
NodeList bodyColumns = (NodeList) bodyExpr.evaluate(document, XPathConstants.NODESET);
for (int i = 0; i < headerColumns.getLength(); i++) {
System.out.println((Attr) headerColumns .item(i)).getValue() + ": " + bodyColumns.item(i).getTextContent());
}Can I assume that XPath will always return the header and body columns in the same order so that they will always match? Or can I even assume that the columns are always returned in document order?
728
The document order is always preserved when using XPath, here's something official for your reference: http://msdn.microsoft.com/en-us/library/ms256090.aspx
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