XML Schema (XSD) - How to specify parent element to contain at least one child element?

Question

I have an XML schema (XSD) that defines an element as mandatory (call it the parent); this parent has, lets say, five child elements, which can all be optional, BUT AT LEAST ONE child element must occur.

How can i specify this in the xsd?

To clarify: The children are different elements and optional. For example.

<Parent>
   <Child1>contents are different to other siblings and arbitrary</Child1>
   <Child2>can be text, a simple element, or another complex element</Child2>
   <Child3>etc.. etc</Child3> 
</Parent>

<xs:complexType name="Parent">
  <xs:sequence>
    <xs:element minOccurs="0" name="Child1" type="xs:string"/>
    <xs:element minOccurs="0" name="Child2" />
    <xs:element minOccurs="0" name="Child3" />
  </xs:sequence>
</xs:complexType>

Even though every child is optional, the parent needs to have at least one child.

Answer 1

There is always the direct approach:

<xs:complexType name="Parent">
  <xs:choice>
    <xs:sequence>
      <xs:element name="Child1"/>
      <xs:element name="Child2" minOccurs="0"/>
      <xs:element name="Child3" minOccurs="0"/>
    </xs:sequence>
    <xs:sequence>
      <xs:element name="Child2"/>
      <xs:element name="Child3" minOccurs="0"/>
    </xs:sequence>
    <xs:sequence>
      <xs:element name="Child3"/>
    </xs:sequence>
  </xs:choice>
</xs:complexType>

Answer 2

Using assertions (I think it is only available in XSD 1.1) it is possible to do the following:

<xs:element name="Parent">
    <xs:complexType>
        <xs:sequence>
            <xs:element name="Child1" type="xs:string" minOccurs="0"/>
            <xs:element name="Child2" minOccurs="0"/>
            <xs:element name="Child3" minOccurs="0"/>
        </xs:sequence>
        <xs:assert test="count(*)>=1"/>
    </xs:complexType>
</xs:element>