XCodeBuild -exportArchive wont allow me to specify filename

Question

I'm busy working on a Jenkins build that will be building iOS applications. I have managed to create an archive successfully with this command:

xcodebuild archive -archivePath build/app.xcarchive 

Now I'm trying to export that archive with specifying the output file name, but can't get this to work.In the example below I want an output file called app.ipa, but all I get is a folder called app.ipa with an ipa file inside name .ipa

xcrun xcodebuild -exportArchive -exportPath build/app.ipa -archivePath build/app.xcarchive/ -exportOptionsPlist exportOptions.plist

Outputs a file /build/app.ipa/<projectname>.ipa

Apples documentation for XCodeBuild says that you can specify the output path including file name:

-exportPath destinationpath Specifies the destination for the exported product, including the name of the exported file.

https://web.archive.org/web/20170620204608/https://developer.apple.com/legacy/library/documentation/Darwin/Reference/ManPages/man1/xcodebuild.1.html

The reason for this is that I would like to keep the build generic so that any project I send through it will result in an app.ipa without me needing to keep track of project names and different output files etc.

Answer 1

This is filed as a bug in open radar: "xcodebuild exportArchive -exportPath" does not write what it's documented to write

Answer 2

For XCode 11 and earlier:

ArchiveAction tag in .xcscheme file can have attribute customArchiveName which can be set to anything you like.

   <ArchiveAction
      buildConfiguration = "AdHoc_Example"
      customArchiveName = "app"
      revealArchiveInOrganizer = "YES">
   </ArchiveAction>
</Scheme>

This will give you app.ipa always when you export the archive through -exportOptionsPlist.