xargs doesn't recognize bash aliases

Question

I'm trying to run the following command:

find . -iname '.#*' -print0 | xargs -0 -L 1 foobar 

where "foobar" is an alias or function defined in my .bashrc file (in my case, it's a function that takes one parameter). Apparently xargs doesn't recognize these as things it can run. Is there a clever way to remedy this?

Answer 1

Since only your interactive shell knows about aliases, why not just run the alias without forking out through xargs?

find . -iname '.#*' -print0 | while read -r -d '' i; do foobar "$i"; done 

If you're sure that your filenames don't have newlines in them (ick, why would they?), you can simplify this to

find . -iname '.#*' -print | while read -r i; do foobar "$i"; done 

or even just find -iname '.#*' | ..., since the default directory is . and the default action is -print.

One more alternative:

 IFS=$'\n'; for i in `find -iname '.#*'`; do foobar "$i"; done 

telling Bash that words are only split on newlines (default: IFS=$' \t\n'). You should be careful with this, though; some scripts don't cope well with a changed $IFS.

Answer 2

Using Bash you may also specify the number of args being passed to your alias (or function) like so:

alias myFuncOrAlias='echo'  # alias defined in your ~/.bashrc, ~/.profile, ... echo arg1 arg2 | xargs -n 1 bash -cil 'myFuncOrAlias "$1"' arg0 echo arg1 arg2 | xargs  bash -cil 'myFuncOrAlias "$@"' arg0