XAMPP Tomcat/Error starting Tomcat

Question

Can someone help me solve this:

"Tomcat Started/Stopped with errors, return code: 1 Make sure you have Java JDK or JRE installed and the required ports are free. Check the "/xampp/tomcat/logs" folder for more information."

I have installed Java JDK. Thanks

Answer 1

Go to https://youtu.be/JmmaeS7UZRk youtube link for better understanding:

1. we need to create an Environment Variable "JAVA_HOME". and give the vale as JDK installation directory path. Ex: "C:\Program Files\Java\jdk1.8.0_66"

2. we need to create an Environment Variable "JRE_HOME". and give the vale as JRE installation directory path. Ex: "C:\Program Files\Java\jre1.8.0_66"

3. Go to your "tomcat" installation directory and then "conf" folder. Ex: "C:\xampp\tomcat\conf".

4. Edit these given files with these values: i) open server.xml file which is located inside conf folder. Go to line number "70" and change the "port" number "8080" as something else for example "9999" and save it. ii) open context.xml file which is located inside "conf" folder and go to line number "19" and change <Context> tag as <Context reloadable="true"> and save it.

5. close the "XAMPP" App and restart it.

6. Now go to the "Config" Option inside "XAMPP" application i.e top right corner of the XAMPP app. then go to the "Service and Port Settings" then go to the "Tomcat" tab and put "9999" as the "HTTP Port" value and save it. Not restart XAMPP.

7. Now try to start "Tomcat" Server.

8. Open your browser and type localhost:9999 in the browser url and hit enter.

Answer 2

Run XAMPP with "Administrator Privileges" to start Tomcat. It is as simple as that.

Answer 3

WINDOWS-KEY + PAUSE (shortcut to System Properties), in system properties choose
Advanced system settings --> Environment variables --> add a new System variable:

Fill in:

Variable name: JAVA_HOME
Variable value: C:\Program Files\Java\jdk1.8.0 (or whatever your location/version is)

klik ok and done(maybe you should restart tomcat after this)