Consider the following:
DateTime = {'2007-01-01 00:00';'2007-02-01 00:00';'2007-03-01 00:00'};
Headers = {'Datetime','Data'};
Dat = [100,200,300];
Data = [DateTime,num2cell(Dat')];
Final = [Headers;Data];
How would I write the data in 'Final' into a tab delimited text file. I know how to use fopen, fprintf and so on when the variable is composed of solely numerical inputs but am struggling to solve this problem. I have tried:
fid = fopen('C:\Documents\test.txt','wt');
fprintf(fid,'%s\t%s\n',Final{:});
fclose(fid);
However, this does not generate a text file that is in the same format as that generated in matlab. How can this problem be solved?
This solution gives what I think you need; some remarks which I hope to be useful are on side
DateTime = {'2007-01-01 00:00';'2007-02-01 00:00';'2007-03-01 00:00'};
Headers = {'Datetime','Data'};
Dat = [100,200,300];
% // In the way you used fprintf it expects just strings ('%s\t%s\n'),
% // therefore Data should be composed exclusively by them.
% // Numbers are converted to strings by using num2str
% // by using cellfun we iteratively convert every element of num2cell(Dat')
% // in strings, obtaining a cell
Data = [DateTime,cellfun(@num2str, num2cell(Dat'), 'UniformOutput' , false )];
Final = [Headers;Data];
fid = fopen('test.txt','wt');
% // this iterates fprintf on the cell rows, giving you the output
cellfun(@(x,y) fprintf(fid,'%s\t%s\n',x,y),Final(:,1),Final(:,2));
fclose(fid);
result
Datetime Data
2007-01-01 00:00 100
2007-02-01 00:00 200
2007-03-01 00:00 300
EDIT:(from comments) in the general case of a N-columns cell, you can simply go for a for loop, e.g.
for i = 1 : size(Final,1)
fprintf(fid,'%s ', Final{i,:} );
fprintf(fid,'\n');
end
(same result, but not depending on the number of columns).
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