WPF: How to start from a window in a different assembly

Question

I googled this and still can't get it working

I have a WPF app and want to start from Main.xaml which is located in a different assembly. Both assemblies are in the same location.

How can I do this? I took out the StartupUri from the XAML and tried with these and some slight variations:

    protected override void OnStartup(StartupEventArgs e)     {         base.OnStartup(e);          StartupUri = new Uri("/CompanyName.VisualStudio.UI;CompanyName/VisualStudio/UI/DatabaseManager/Main.xaml", UriKind.Relative);         //StartupUri = new Uri(@"pack://application:,,,/ CompanyName.VisualStudio.UI;CompanyName/VisualStudio/UI/DatabaseManager/Main.xaml");      } 

The name of the assembly is "CompanyName.VisualStudio.UI" and the namespace is "CompanyName/VisualStudio/UI/DatabaseManager/Main.xaml"

Any ideas?

Answer 1

This article gives a clean XAML-only solution.

StartupUri="pack://application:,,,/assembly_name;component/path/file_name.xaml" 

Where:

• assembly_name is the name of the referenced assembly, sans extension
• path is the subfolder in which the component resides; if the component is at the project root, this element is omitted
• file_name is the file name of the component

Examples:

pack://application:,,,/UI;component/CalculatorView.xaml assembly - UI.dll path - none (file at project root) file_name - CalculatorView  pack://application:,,,/MyApp.UI;component/Views/CalculatorView.xaml assembly - MyApp.UI.dll path - Views file_name - CalculatorView  pack://application:,,,/UI;component/Views/External/CalculatorView.xaml assembly - UI.dll path - Views/External file_name - CalculatorView