WPF: How do I set the Owner Window of a Dialog shown by a UserControl?

Question

I've got a WPF application with these three types of things...

• WindowMain
• UserControlZack
• WindowModal

UserControlZack1 sits on my WindowMain...

<Window x:Class="WindowMain"         xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"         xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"         xmlns:local="clr-namespace:ProjectName"         ...         Name="WindowMain">     <Grid>         ...         <local:UserControlZack x:Name="UserControlZack1" ... />         ...     </Grid> </Window> 

UserControlZack1 displays a WindowModal dailog box...

 Partial Public Class UserControlZack     ...      Private Sub SomeButton_Click(...)         'instantiate the dialog box and open modally...         Dim box As WindowModal = New WindowModal()         box.Owner = ?????         box.ShowDialog()         'process data entered by user if dialog box is accepted...         If (box.DialogResult.GetValueOrDefault = True) Then             _SomeVar = box.SomeVar             ...         End If     End Sub  End Class 

How do I set box.Owner to the correct Window, my running instance of WindowMain?

I cannot use box.Owner = Me.Owner, because "'Owner' is not a member of 'ProjectName.UserControlZack'."

I cannot use box.Owner = Me.Parent, because that returns a Grid, not the Window.

I cannot use box.Owner = WindowMain, because "'WindowMain' is a type and cannot be used as an expression."

Answer 1

Try to use

.Owner = Window.GetWindow(this) 

Answer 2

To get the top level window your control is in, assuming there is one:

(Window)PresentationSource.FromVisual(this).RootVisual 

To get the main window:

Application.Current.MainWindow