
How can I implement javascript function to calculate frequency of each word in a given sentence.
this is my code:
function search () {
  var data = document.getElementById('txt').value;
  var temp = data;
  var words = new Array();
  words = temp.split(" ");
  var uniqueWords = new Array();
  var count = new Array();
  for (var i = 0; i < words.length; i++) {
    //var count=0;
    var f = 0;
    for (j = 0; j < uniqueWords.length; j++) {
      if (words[i] == uniqueWords[j]) {
        count[j] = count[j] + 1;
        //uniqueWords[j]=words[i];
        f = 1;
      }
    }
    if (f == 0) {
      count[i] = 1;
      uniqueWords[i] = words[i];
    }
    console.log("count of " + uniqueWords[i] + " - " + count[i]);
  }
}
am unable to trace out the problem ..any help is greatly appriciated. output in this format: count of is - 1 count of the - 2..
input: this is anil is kum the anil
Here is a JavaScript function to get the frequency of each word in a sentence:
function wordFreq(string) {
    var words = string.replace(/[.]/g, '').split(/\s/);
    var freqMap = {};
    words.forEach(function(w) {
        if (!freqMap[w]) {
            freqMap[w] = 0;
        }
        freqMap[w] += 1;
    });
    return freqMap;
}
It will return a hash of word to word count. So for example, if we run it like so:
console.log(wordFreq("I am the big the big bull."));
> Object {I: 1, am: 1, the: 2, big: 2, bull: 1}
You can iterate over the words with Object.keys(result).sort().forEach(result) {...}. So we could hook that up like so:
var freq = wordFreq("I am the big the big bull.");
Object.keys(freq).sort().forEach(function(word) {
    console.log("count of " + word + " is " + freq[word]);
});
Which would output:
count of I is 1
count of am is 1
count of big is 2
count of bull is 1
count of the is 2
JSFiddle: http://jsfiddle.net/ah6wsbs6/
And here is wordFreq function in ES6:
function wordFreq(string) {
  return string.replace(/[.]/g, '')
    .split(/\s/)
    .reduce((map, word) =>
      Object.assign(map, {
        [word]: (map[word])
          ? map[word] + 1
          : 1,
      }),
      {}
    );
}
JSFiddle: http://jsfiddle.net/r1Lo79us/
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