will goto violate mutexes?

Question

I am doing it wrong, yes?

...
if( you_think_youre_genius )
    goto goto_sucks:
...
pthread_mutex_lock(&mutex);

    do_stuff();

    goto_sucks:
        do_other_stuff();

pthread_mutex_unlock(&mutex);

Answer 1

Yes, goto is direct jmp down at the binary code level so any function calls between the goto and the label will be skipped, period.

Answer 2

The mutex is acquired inside the pthread_mutex_lock function. If you jump past the function call, you will not have acquired the mutex. If you try to lock a mutex twice, you may deadlock. If you try to unlock a mutex you do not own, you may break things very badly.

Answer 3

If the condition is true, do_other_stuff will be called without the mutex being locked, and then the mutex will be released without locking it. Plain wrong!

Just without goto

if( you_think_youre_genius )  
    {  
         pthread_mutex_lock(&mutex);    
     }   
else  
{   
...     
pthread_mutex_lock(&mutex);   
//Assumming no expetion thrown   
do_stuff();   
}   
do_other_stuff();    
pthread_mutex_unlock(&mutex);