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The answer is yes, it will check every if statements. The reason is simple, you are not breaking out of the loop after a condition is evaluated to true.
No, if the first condition returns false then the whole expression automatically returns false. Java will not bother examining the other condition.
With the if/else statement, the program will execute either the true code block or the false code block so something is always executed with an if/else statement.
If condition_n evaluates to TRUE, the program will execute instructions in the ELSEIF block and skip the ELSE block. However, if condition_n evaluates to FALSE, then the program will move to execute the ELSE Block. When evaluating the conditions sequentially, only a single code block can be executed at a time.
It will stop evaluating because you're using the double ampersand && operator. This is called short-circuiting.
If you changed it to a single ampersand:
if(myList.Count > 0 & myString.Equals("value"))
it would evaluate both.
No, it will not be considered. (This is known as short circuiting.)
The compiler is clever enough (and required by language specification) to know that if the first condition is false, there is no way to expression will evaluate to true.
And as Jacob pointed for ||, when the first condition is true, the second condition will not be evaluated.
If the logical operator is AND (&&) then IF statement would evaluate first expression - if the first one is false, it would not evaluate second one. This is useful to check if variable is null before calling method on the reference - to avoid null pointer exception
If the logical operator is OR (||) then IF statement would evaluate first expression - if the first one is true, it would not evaluate second one.
Compilers and runtimes are optimized for this behavior
No, second condition will be skipped if you use &&,
If you use & it will be considered
Consider the folowing:
static int? x;
static int? y;
static void Main(string[] args)
{
x = 5;
if (testx() & testy())
{
Console.WriteLine("test");
}
}
static Boolean testx()
{
return x == 3;
}
static Boolean testy()
{
return y == 10;
}
If you trace through both the testx and testy functions are evaulated even though testx was false.
If you change the test to && only the first was checked.
In your example, the second statement will only be evaluated if the first fails. The logical AND && will only return true when both operands are true, aka short circuit evaluation.
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