Menu
int main()
{
char *temp = "Paras";
int i;
i=0;
temp[3]='F';
for (i =0 ; i < 5 ; i++ )
printf("%c\n", temp[i]);
return 0;
}
Why temp[3]='F'; will cause segmentation fault since temp is not const?
314
Overview. A segmentation fault (aka segfault) is a common condition that causes programs to crash; they are often associated with a file named core . Segfaults are caused by a program trying to read or write an illegal memory location.
Tip: A segmentation fault (also known as segfault) is a common condition that causes programs to crash; A segmentation fault is typically caused by a program trying to read from or write to an illegal memory location, that is, part of the memory to which the program is not supposed to have access.
Core Dump (Segmentation fault) in C/C++ Core Dump/Segmentation fault is a specific kind of error caused by accessing memory that “does not belong to you.” When a piece of code tries to do read and write operation in a read only location in memory or freed block of memory, it is known as core dump.
Dereferencing or assigning to an uninitialized pointer (wild pointer, which points to a random memory address) Dereferencing or assigning to a freed pointer (dangling pointer, which points to memory that has been freed/deallocated/deleted) A buffer overflow. A stack overflow.
You are not allowed to modify string literals.
74
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
