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Why shouldn't we have dynamic allocated memory with different size in embedded system

I have heard in embedded system, we should use some preallocated fixed-size memory chunks(like buddy memory system?). Could somebody give me a detailed explanation why? Thanks,

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Hao Shen Avatar asked Jan 26 '14 22:01

Hao Shen


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1 Answers

In embedded systems you have very limited memory. Therefore, if you occasionally lose only one byte of memory (because you allocate it , but you dont free it), this will eat up the system memory pretty quickly (1 GByte of RAM, with a leak rate of 1/hour will take its time. If you have 4kB RAM, not as long)

Essentially the behaviour of avoiding dynamic memory is to avoid the effects of bugs in your program. As static memory allocation is fully deterministic (while dynamic memory alloc is not), by using only static memory allocation one can counteract such bugs. One important factor for that is that embedded systems are often used in security-critical application. A few hours of downtime could cost millions or an accident could happen.

Furthermore, depending on the dynamic memory allocator, the indeterminism also might take an indeterminate amount of time, which can lead to more bugs especially in systems relying on tight timing (thanks to Clifford for mentioning this). This type of bug is often hard to test and to reproduce because it relies on a very specific execution path.

Additionally, embedded systems don't usually have MMUs, so there is nothing like memory protection. If you run out of memory and your code to handle that condition doesn't work, you could end up executing any memory as instruction (bad things could happen! However this case is only indirectly related to dynamic mem allocation).

As Hao Shen mentioned, fragmentation is also a danger. Whether it may occur depends on your exact usecase, but in embedded systems it is quite easy to loose 50% of your RAM due to fragmentation. You can only avoid fragmentation if you allocate chunks that always have the exact same size.

Performance also plays a role (depends on the usecase - thanks Hao Shen). Statically allocated memory is allocated by the compiler whereas malloc() and similar need to run on the device and therefore consume CPU time (and power).

Many embedded OSs (e.g. ChibiOS) support some kind of dynamic memory allocator. But using it only increases the possibility of unexpected issues to occur.

Note that these arguments are often circumvented by using smaller statically allocated memory pools. This is not a real solution, as one can still run out of memory in those pools, but it will only affect a small part of the system.

As pointed out by Stephano Sanfilippo, some system don't even have enough resources to support dynamic memory allocation.

Note: Most coding standard, including the JPL coding standard and DO-178B (for critical avionics code - thanks Stephano Sanfilippo) forbid the use of malloc.

I also assume the MISRA C standard forbids malloc() because of this forum post -- however I don't have access to the standard itself.

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Uli Köhler Avatar answered Oct 05 '22 23:10

Uli Köhler