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why private value of the obj can be changed by class instance?

Tags:

c++

#include<iostream>
using namespace std;

class A
{
    private:
        int value;
    public:
        A(int init):value(init){}
        void changevalue(A &a){a.value = 100;}//why a's value can be changed?
        void printvalue(){cout << value << endl;}
};

int main(int argc , char *argv[])
{
    A a(2);
    A b(3);

    a.changevalue(b);
    b.printvalue();

    return 0;
}

a is an instance of A class,with a private value named value,but why this private value can be changed? Is that the parameter list included in the scope of class?

like image 450
std Avatar asked Dec 09 '22 21:12

std


2 Answers

Because class access specifier apply on per class basis and not per object basis.

You can always modify the same type of object inside the class functions.Usual examples are copy constructor and copy assignment operator.

like image 100
Alok Save Avatar answered Feb 23 '23 01:02

Alok Save


private doesn't mean "private to the object identity" but "private to the type (and friends)".

Note that accessibility and being able to write to the type are orthogonal concepts. You can always access a private value inside an object of your own type, but whether you can write to it or not depends on if the object is declared as const:

void f(A& a){ a.value = 4; } // OK: 'a' is not 'const'
void g(A const& a){ a.value = 4 } // error: 'a' is marked as ' const'
like image 35
Xeo Avatar answered Feb 23 '23 00:02

Xeo