why n*n results as 4 at the first instant of the loop ? to me it should be 1*1. instead it comes as 2*2 [duplicate]

Question

Why "n*n" results as 4 at the first instant of the loop? to me it should be 1*1. instead it comes as 2*2.

Please give me a simple answer as i'm still a beginner :)

#include <iostream>
using namespace std;
int main(){

    int n =1 , *p;
    p = &n;

    char aString[] = {"student"};

    for (int i = 0; i<5; i++)

        cout<< "i = "<< i << "n*n = "<<n*n<< "n++ = "<< n++<< " *p "<<endl; 

    system ("pause");
    return 0;
 }

http://ideone.com/nWugmm

Answer 1

The evaluation order of elements in an expression is unspecified, except some very particular cases, such as the && and || etc.

writing:

cout<< "i = "<< i << "n*n = "<<n*n<< "n++ = "<< n++<< " *p "<<endl;

you suppose an order and in particulr that n++ is the last evaluated.

To solve this problem you could split the exression in two parts:

cout<< "i = "<< i << "n*n = "<<n*n<< "n++ = "<< n<< " *p "<<endl;
n++;