Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Why need useRef and not mutable variable?

I have read A Complete Guide to useEffect - Swimming Against the Tide at Overreacted.

The example shows that if we want to get the latest count, we can use useRef to save the mutable variable, and get it in async function laster:

function Example() {   const [count, setCount] = useState(0);   const latestCount = useRef(count);    useEffect(() => {     // Set the mutable latest value     latestCount.current = count;     setTimeout(() => {       // Read the mutable latest value       console.log(`You clicked ${latestCount.current} times`);     }, 3000);   });   // ... } 

However, I can do the same thing by creating a variable outside the component function, such as:

import React, { useState, useEffect, useRef } from 'react';  // defined a variable outside function component let countCache = 0;  function Counter() {   const [count, setCount] = useState(0);   countCache = count;       // set default value    useEffect(() => {     setTimeout(() => {       // We can get the latest count here       console.log(`You clicked ${countCache} times (countCache)`);     }, 3000);   });   // ... }  export default Counter; 

Are both ways practical, or is there anything bad if I define the variable outside function component?

like image 626
PJCHENder Avatar asked Aug 10 '19 17:08

PJCHENder


People also ask

When should we use useRef?

The useRef Hook allows you to persist values between renders. It can be used to store a mutable value that does not cause a re-render when updated. It can be used to access a DOM element directly.

Which cases should you use useRef?

useRef can be used to store local mutable value in a component. It doesn't participate in rerendering (unline state data). useMemo is used to memoize (like we do in Dynamic Programming, concept wise) and skip recalculation.

Is useRef immutable?

If the useRef is initialized with null and the initial value does not belong to the provided type, the current property is immutable.

Is the return value of useRef mutable?

useRef returns a mutable ref object whose .current property is initialized to the passed argument ( initialValue ). The returned object will persist for the full lifetime of the component. Essentially, useRef is like a “box” that can hold a mutable value in its .current property.


1 Answers

useRef will assign a reference for each component, while a variable defined outside a function component scope will only assigned once.

useRef reference life span is component's life span (it "dies" when the component unmounts, while JS variables are scope-blocked).

Hence, define constant purpose variables outside of the component scope:

// This statement will only called once const DEFAULT_VALUE = 5;  function Component() {   // use DEFAULT_VALUE. } 

Defining the same statement inside component's scope, will redefine it on every render:

// We can do better function Component() {   // Redefined on every render   const DEFAULT_VALUE = 5; } 

Now for the question:

First, we can't actually reflect UI changed with outer scoped variables since changing them does not trigger render (only React API does).

Therefore the reflected value is its closure value.

let countCache = 0;  function Counter() {   ...   countCache = 0;    useEffect(() => {     countCache = count;   });   ...    // closure value of countCache   return <div>{countCache}</div> } 

Now, whats special with outer scope variables that they are global to the module itself, so using its value is global to all components referencing it (in the module).

For example if you want to count how many times the component mounted in your whole application life span, increase the variable inside useEffect on mount (couldn't find any other possible use-case).

let howMuchMounted = 0;  function Component() {   useEffect(() => { howMuchMounted += 1, [] }; } 

To reflect the differences of outer variable and useRef reference, in the next example, on button click, you may notice that the variable is global for both of the components, while the reference is always updated to current state value.

import React, { useEffect, useRef, useReducer } from "react"; import ReactDOM from "react-dom";  // defined a variable outside function component let countCache = 0;  function Counter() {   const [num, count] = useReducer((num) => num + 1, 0);    const countRef = useRef(count);    useEffect(() => {     // set count value on count change     countCache = num;     countRef.current = num;   }, [num]);    return (     <>       <button onClick={count}>Count</button>       <h3>state {num}</h3>       <h3>variable {countCache}</h3>       <h3>reference {countRef.current}</h3>     </>   ); }  export default function App() {   return (     <>       <Counter />       <hr />       See what happens when you click on the other counter       <hr />       <Counter />     </>   ); } 

Please see a follow up question on useEffect use cases, there are many common mistakes when working with useRef references inside useEffect.

Edit useRef vs Variable

like image 97
Dennis Vash Avatar answered Oct 01 '22 18:10

Dennis Vash