I just discovered the following odd behavior with String#split
:
"a\tb c\nd".split
=> ["a", "b", "c", "d"]
"a\tb c\nd".split(' ')
=> ["a", "b", "c", "d"]
"a\tb c\nd".split(/ /)
=> ["a\tb", "c\nd"]
The source (string.c from 2.0.0) is over 200 lines long and contains a passage like this:
/* L 5909 */
else if (rb_enc_asciicompat(enc2) == 1) {
if (RSTRING_LEN(spat) == 1 && RSTRING_PTR(spat)[0] == ' '){
split_type = awk;
}
}
Later, in the code for the awk
split type, the actual argument isn't even used any more and does the same as a plain split
.
It's consistent with Perl's split()
behavior. Which in turn is based on Gnu awk
's split()
. So it's a long-standing tradition with origins in Unix.
From the perldoc on split
:
As another special case, split emulates the default behavior of the command line tool awk when the PATTERN is either omitted or a literal string composed of a single space character (such as ' ' or "\x20" , but not e.g. / / ). In this case, any leading whitespace in EXPR is removed before splitting occurs, and the PATTERN is instead treated as if it were /\s+/ ; in particular, this means that any contiguous whitespace (not just a single space character) is used as a separator. However, this special treatment can be avoided by specifying the pattern / / instead of the string " " , thereby allowing only a single space character to be a separator.
Check out the documentation, this part in particular:
If pattern is a String, then its contents are used as the delimiter when splitting str. If pattern is a single space, str is split on whitespace, with leading whitespace and runs of contiguous whitespace characters ignored.
If pattern is omitted, the value of $; is used. If $; is nil (which is the default), str is split on whitespace as if ` ‘ were specified.
You can use a regexp to split the string.
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