I have a simple WPF Popup that I am showing when the user clicks a Button.
<Button
x:Name="aButton"
Content="Up/Down"
Width="75"
Height="30"
Click="aButton_Click"
/>
<Popup
PlacementTarget="{Binding ElementName=aButton}"
Placement="Right"
VerticalOffset="-31"
StaysOpen="False"
AllowsTransparency="True"
>
<StackPanel>
<Button Width="45" Height="45" Margin="2,0,2,2" Content="+"/>
<Button Width="45" Height="45" Margin="2,0,2,0" Content="-"/>
</StackPanel>
</Popup>
What is extremely weird ... is that this code works differently depending on what machine it runs on.
I run this code on my main desktop and everything works just fine ... and as it should. I run it on my PDC09 netbook ... and the Popup shows opposite (on the left instead of the right as I told it to with the Placement property).
Why is this? And what can I do about it?
I couldn't find anything via Google ... but a lucky search in the WPF forum, quickly found this post. Note to self: don't forget to search the WPF forums if Google can't find anything.
The answer is that my PDC09 netbook is a Tablet PC at heart, and apparently, Microsoft thought it was a good idea to show the Popup opposite to the Placement property on a Tablet PC that is configured for right-handed people ... such that the Popup doesn't appear under the user's hand.
The solution is to revert to custom Popup placement ... if you don't want this behavior.
I would love to hear about any other ways around this problem.
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