Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Why is Image.Save(Stream, ImageFormat) throwing an exception?

I am trying to convert an image to an icon. My function is:

private Icon GenerateIcon(int width, int height)
{
    using (Bitmap icon = _backingImage.GetThumbnailImage(width, height, () => false, System.IntPtr.Zero) as Bitmap)
    using(MemoryStream imgStream = new MemoryStream())
    {
        icon.Save(imgStream, System.Drawing.Imaging.ImageFormat.Icon);
        return new Icon(imgStream);
    }
}

But when the programme calls the method, it throws an ArgumentNullException("encoder") where I'm calling icon.Save.

I find this odd because I'm not passing in an encoder, I want the framework to figure out what the encoder should be, which is why I'm passing in an ImageFormat.

Is it that there aren't any encoders for ImageFormat.Icon, or is there something I'm doing wrong?

like image 477
Matt Ellen Avatar asked Nov 13 '10 10:11

Matt Ellen


2 Answers

You guessed it right: GDI+ only supports an ICON decoder.

You might want to perform the conversion yourself. In that case, see http://www.codeproject.com/KB/GDI-plus/safeicon.aspx.

like image 162
Frédéric Hamidi Avatar answered Sep 30 '22 05:09

Frédéric Hamidi


Just convert image to icon:

Icon myIcon = Icon.FromHandle(((Bitmap)myImage).GetHicon())

and then save it using stream:

myIcon.Save(myStream);

regards, Kate

like image 35
SmartK8 Avatar answered Sep 30 '22 04:09

SmartK8