In this snippet of Google Closure javascript code involving a constructor, why is goog.base(this);
necessary? Doesn't Foo
already inherit from Disposable with goog.inherits(foo, goog.Disposable);
?
goog.provide('Foo');
/**
* @constructor
* @extends {goog.Disposable}
*/
Foo = function() {
goog.base(this);
}
goog.inherits(foo, goog.Disposable);
foo.prototype.doSomething = function(){
...
}
foo.prototype.disposeInternal = function(){
...
}
In JavaScript, this
is set entirely by how the function is called, not where it's defined (as it is in Java, C#, and C++). So to make this
within the call to goog.Disposable
be the this
of where you're calling it, you have to use .call
or .apply
. Otherwise, if you just called goog.Disposable()
, within the call this
would be goog
.
Basically, there are two ways to set this
for the function you're calling:
Use obj.func()
or obj["func"]()
notation — e.g., make the call as part of the same overall expression where you're retrieving a property from the object. This tells the engine that within the call, you want this
to refer to obj
.
Use call
or apply
to be more explicit about it by supplying the object to use as this
as the first argument. The only difference between call
and apply
is how you supply other arguments: With call
, you supply them as discrete args, e.g. foo.call(obj, 1, 2, 3)
calls foo
with this
set to obj
and the arguments 1
, 2
, and 3
. With apply
, you supply the arguments as an array-like second argument: foo.apply(obj, [1, 2, 3]);
(note the [
and ]
; e.g. var a = [1, 2, 3]; foo.call(obj, a);
More to explore:
this
goog.inherits()
establishes the prototype chain from the child constructor
to the parent constructor.
/**
* Inherit the prototype methods from one constructor into another.
* @param {Function} childCtor Child class.
* @param {Function} parentCtor Parent class.
*/
goog.inherits = function(childCtor, parentCtor) {
/** @constructor */
function tempCtor() {};
tempCtor.prototype = parentCtor.prototype;
childCtor.superClass_ = parentCtor.prototype;
childCtor.prototype = new tempCtor();
/** @override */
childCtor.prototype.constructor = childCtor;
};
In addition to prototype properties, constructors may have "own" properties
(i.e. instance-specific properties added to this
). Since goog.inherits()
does not call the parent constructor, own properties are not copied to the
child constructor and any initialization code in the parent does not get
executed. For these reasons, the standard pattern is to chain constructors as in the following example.
/**
* @param {string} name The parent's name.
* @constructor
*/
var Parent = function(name) {
/**
* @type {string}
* @private
*/
this.name_ = name;
}
/**
* @param {string} name The child's name.
* @constructor
* @extends {Parent}
*/
var Child = function(name) {
Parent.call(this, name);
}
goog.inherits(Child, Parent);
goog.base()
is a helper function for calling parent methods so that you do
not need to explicitly use call() or apply().
If [goog.base()] is called from a constructor, then this calls the superclass contructor with arguments 1-N.
If this is called from a prototype method, then you must pass the name of the method as the second argument to this function. If you do not, you will get a runtime error. This calls the superclass' method with arguments 2-N.
This function only works if you use
goog.inherits
to express inheritance relationships between your classes.
In Closure code it is common to chain constructors with goog.base()
rather
than calling the parent constructor explicitly.
/**
* @param {string} name The child's name.
* @constructor
* @extends {Parent}
*/
var Child = function(name) {
goog.base(this, name);
}
goog.inherits(Child, Parent);
goog.inherits()
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