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Why is an extra semicolon not allowed after the return statement, when it is allowed for other statements?

I put an extra semicolon after the semicolon of System.out.println:

System.out.println();;

Which was legal to Java compiler, so I checked for other statements and they were all legal too. So when I searched and found these links:

  1. Why does Java not show an error for double semicolon at the end of a statement?

  2. Compiler doesn't complain when I ended a line with two semicolons. Why?

  3. When would you put a semicolon after a method closing brace?

  4. Why does code with successive semi-colons compile?

  5. Semicolon at end of 'if' statement

I came to understand that an extra semicolon means an extra empty statement.

But when I put an extra semicolon after a return statement, I got a compile time error. I came to the conclusion that the return statement is considered to be the last statement in the flow of execution, so putting an extra statement after the return is illegal.

The same thing happens in this code too:

if(a == b)
    System.out.println();;
else
    System.out.println();

Inside the if statement System.out.println();; gives a compile time error, because the compiler is expecting elseif or else. Am I right or is is there some other reason?

like image 551
Arun Sudhakaran Avatar asked Dec 29 '17 13:12

Arun Sudhakaran


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2 Answers

Why multiple semicolon is not allowed after the return statement, when it is allowed for all other statement?

Simply because when you have a statement like

System.out.println();;

This means you have two statements, one is System.out.println(); and other statement is after the first semi colon, it is empty and that's allowed BUT you can't have any empty statement or any other statement after the return statement because it will never execute, in other words, its unreachable statement and you can't have unreachable statements in your code.

Same thing happens in this code too

if(a == b)
    System.out.println();;
else
    System.out.println();

that's because, when you have an else statement, statement just before it should be if statement which is not the case in above code snippet because statement just before else statement is an empty statement which is not allowed.

If you have parenthesis after the if statement like

if(a == b) {
    System.out.println();;
}
else
   System.out.println();

you will get no errors because now empty statement is inside an if block and the statement just before else is if statement and not the empty statement which was the case when you had no parenthesis after if statement

like image 159
Yousaf Avatar answered Sep 30 '22 16:09

Yousaf


Your code:

if (a == b)
    System.out.println();;
else
    System.out.println();

is equivalent to

if (a == b) System.out.println();
;
else System.out.println();

And you can't use an else if the preceding statement is not an if.

like image 39
assylias Avatar answered Sep 30 '22 17:09

assylias